The voltage in the two circuits below is the same, but the two-bulb circuit draws more total current. Why? To answer the question, consider that current flowing out of the battery obeys Ohm’s law. The current is the battery voltage divided by the total resistance of the circuit. What resistance does the battery “see?”

Analyzing a parallel circuit

According to Ohm’s law, the current in each branch of the circuit is the battery voltage V divided by the resistance of that branch (R_{1} or R_{2}). Next, note that the current flowing out of the battery is the sum of the currents in the two branches (from Kirchhoff’s current law).

If you compare this with Ohm’s law, the inverse of the total resistance as seen by the battery is equal to the sum of the inverses of the individual branch resistances. This leads directly to equation (17.4), which gives the total resistance R for a parallel circuit containing three individual resistances:

Adding more branches to a parallel circuit always increases the total current in the circuit. From the perspective of the battery, the total resistance of the circuit must decrease, because more total current flows while the voltage stays the same (equation 17.4).

Adding resistances in parallel

What is the equivalent resistance of two 10 Ω resistors connected in parallel?

If you connect three identical resistors in series and in parallel, in which case will they have a smaller equivalent resistance?

The resistors connected in parallel will have a smaller total resistance. The series resistors will have a total circuit resistance of 3R, whereas the parallel resistors will have a total circuit resistance of R/3. In a parallel circuit, the total circuit resistance will always be less than any of the individual resistances. In a series circuit, the total circuit resistance will always be greater than each of the individual resistors.